How do you find the exact value for #sec 315#? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Nghi N. Oct 10, 2015 Find sec 315 Ans: #sqrt2# Explanation: #sec (315) = 1/(cos 315).# Find cos (315) #cos (315) = cos (-45 + 360) = cos (-45) = cos (45) = sqrt2/2# Therefor, #sec 315 = 1/(cos 45) = 2/sqrt2 = sqrt2# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 14752 views around the world You can reuse this answer Creative Commons License