How do you find the exact value of $a r c sin (\frac{\sqrt{3}}{2})$ $arc sin (sqrt3/2)$ ?

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How do you find the exact value of $a r c sin (\frac{\sqrt{3}}{2})$ $arc sin (sqrt3/2)$ ?

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Answer 1 · 2015-05-15T11:22:46

If $θ = arcsin (\frac{\sqrt{3}}{2})$ $theta = arcsin(sqrt(3)/2)$
then
$sin (θ) = \frac{\sqrt{3}}{2}$ $sin(theta) = sqrt(3)/2$

This implies one of the standard trigonometric triangles:
enter image source here
with $θ = 60^{o} = \frac{π}{3} radians$ $theta = 60^o = pi/3 "radians"$ (if we restrict ourselves to the first quadrant)

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How do you find the exact value of $a r c sin (\frac{\sqrt{3}}{2})$ $arc sin (sqrt3/2)$ ?

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