How do you find the exact value of $arccos (cos (- 5 π))$ $arccos(cos(-5pi))$ ?

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Answer 1 · 2017-01-15T11:25:39

$15°42'$ 28.6"#

$arccos(cos(-5pi))$

$=arccos(cos(-15.70796327)$

$=arccos(cos-15.70796327)$

$=arccos(0.962654127)$

$=15.70796327$

$=15°42'$ 28.6"

How do you find the exact value of arccos(cos(-5pi))arccos(cos(−5π))arccos(cos(-5pi))?