How do you find the exact value of $arcsin (- 1)$ $arcsin(-1)$ ?

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Answer 1 · 2017-02-10T21:46:30

$arcsin(-1)=-90+360k, k in ZZ$

If we set $x=arcsin(-1)$ , then $sinx=-1$

This is easy to solve as we know a sinusoidal wave touches $y=-1$ at $-90, 270, 630$ etc.

How do you find the exact value of arcsin(-1)arcsin(−1)arcsin(-1)?