How do you find the exact value of $arcsin (sin (7 \cdot \frac{π}{3}))$ $arcsin(sin(7*pi/3))$ ?

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Answer 1 · 2016-03-11T17:24:06

$arcsin (sin (7 \cdot \frac{π}{3})) = \frac{7 π}{3}$ $arcsin(sin(7*pi/3))=(7pi)/3$

As arcsin and sin are inverse ratios, hence $arcsin (sin θ) = θ$ $arcsin(sintheta)=theta$ .

Hence, $arcsin (sin (7 \cdot \frac{π}{3})) = \frac{7 π}{3}$ $arcsin(sin(7*pi/3))=(7pi)/3$ .

How do you find the exact value of arcsin(sin(7*pi/3))arcsin(sin(7⋅π3))arcsin(sin(7*pi/3))?