How do you find the exact value of $arctan (tan (\frac{2 π}{3}))$ $arctan(tan ((2pi)/3))$ ?

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Answer 1 · 2015-06-23T03:58:29

$\frac{tan (2 π)}{3} = - \sqrt{3}$ $tan (2pi)/3 = -sqrt3$

$tan (- \sqrt{3})$ $tan (-sqrt3)$ --> $a r c x = \frac{2 π}{3} + K π$ $arc x = (2pi)/3 + Kpi$

How do you find the exact value of arctan(tan(2π3)) arctan(tan ((2pi)/3))?