How do you find the exact value of ${cos}^{- 1} (\frac{1}{2})$ $cos^-1(1/2)$ ?

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Answer 1 · 2016-08-21T19:05:16

60 degrees

${cos}^{- 1}$ $cos^-1$ (1/2)
means the angle whose cosine is $\frac{1}{2}$ $1/2$

Draw an equilateral triangle , cut it in half,: the ratio of the sides

is 1:2: $\sqrt{3}$ $sqrt3$

The angle whose cosine is $\frac{1}{2}$ $1/2$ is 60 degrees.

How do you find the exact value of cos−1(12)cos^-1(1/2)?