How do you find the exact value of #log_2 sqrt2#? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer bp Feb 10, 2017 #1/2# Explanation: #log_2 sqrt2 =log_2 2^(1/2)# =#1/2 log_2 2# (#log_2 2# equals 1) =#1/2# Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 11036 views around the world You can reuse this answer Creative Commons License