How do you find the exact value of ${sin}^{- 1} (sin (\frac{5 π}{8}))$ $sin ^-1 ( sin( (5pi)/8) )$ ?

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Answer 1 · 2016-08-08T06:00:45

$\frac{5 π}{8}$ $(5pi)/8$

Use $f^{- 1} f (x) = x$ $f^(-1)f(x)=x$

Here, f is sin and $x = \frac{5}{8} π$ $x=5/8pi$

How do you find the exact value of sin−1(sin(5π8))sin ^-1 ( sin( (5pi)/8) )?