How do you find the exact value of #sin^-1(sin((7pi)/4))#?
1 Answer
Aug 2, 2016
Explanation:
#sin^-1 x color(blue)" is the inverse of " sinx# and in general
#color(red)(|bar(ul(color(white)(a/a)color(black)(f^-1(f(x))=x)color(white)(a/a)|)))#
#rArrsin^-1(sin((7pi)/4))=(7pi)/4#
