How do you find the exact value of ${sin}^{- 1} (- \frac{\sqrt{2}}{2})$ $sin^-1(-sqrt2/2)$ ?

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Answer 1 · 2017-02-05T17:31:30

$- 45$ $-45$

${sin}^{- 1} (- \frac{\sqrt{2}}{2})$ $sin^-1(-sqrt2/2)$

${sin}^{- 1} = arcsin$ $sin^-1=arcsin$

$:.sin^-1(-1.414213562/2)$

$:.sin^-1(-0.707106781)$

$:.=-45$

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