Question

How do you find the exact value of `sin(arccos(1/2))`?

Answer 1

`sin(arccos(1/2))=sqrt3/2`

Explanation:

As `cos(pi/3)=1/2`

`arccos(1/2)=pi/3`

Hence, `sin(arccos(1/2))=sin(pi/3)=sqrt3/2`