How do you find the exact value of sin(arcsin (1/6))sin(arcsin(16))?
1 Answer
Jun 7, 2016
Explanation:
arcsinx
=sin^-1x" the inverse sin of x"=sin−1x the inverse sin of x What this tells us is that
sin^-1x" is the inverse function of sinx"sin−1x is the inverse function of sinx The inverse function 'undoes' what the function does.
rArrsin(sin^-1(1/6))=1/6⇒sin(sin−1(16))=16
