How do you find the exact value of ${tan}^{- 1} (1)$ $tan^-1(1)$ ?

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Answer 1 · 2017-08-21T11:21:13

$45^{0}$ $45^0$

because you know that
$tan (45) = 1$ $tan(45)=1$

so ${tan}^{- 1} (1)$ $tan^-1(1)$ equal to the $θ$ $theta$

which here equals to 45

so you are getting it by your background of the value of theta and just reverse, and I don't think there is a direct or simple way to do that.

or simply by using calculator

How do you find the exact value of tan^-1(1)tan−1(1)tan^-1(1)?