Question

How do you find the excluded values of `\frac{2x+1}{x^2-x-6}`?

Answer 1

Since denominators cannot be zero, we have

`x^2-x-6 ne 0`

by factoring out,

`(x+2)(x-3) ne 0 => x ne -2, 3`

Hence, `x=-2` and `x=3` are its excluded values.

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I hope that this was helpful.