How do you find the factors of $f(z)$ over C if $f(z)=2z^3+3z^2-14z-15$ ?

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Answer 1 · 2016-09-17T19:14:22

$(z+1)(z+3)(2z-5)$ .

We observe that,

The Sum of the co-effs. of odd powered terms of $z$ is

$2-14=-12$ ,

and, that of even powered, $3-15=-12$

We conclude that $(z+1)$ is a factor of $f(z)$ .

$"Now, "f(z)=2z^3+3z^2-14z-15$

$=ul(2z^3+2z^2)+ul(z^2+z)-ul(15z-15)$

$=2z^2(z+1)+z(z+1)-15(z+1)$

$=(z+1)(2z^2+z-15)$

$=(z+1){ul(2z^2+6z)-ul(5z-15)}$

$=(z+1){2z(z+3)-5(z+3)}$

$=(z+1)(z+3)(2z-5)$ .

How do you find the factors of f(z)f(z) over C if f(z)=2z^3+3z^2-14z-15f(z)=2z^3+3z^2-14z-15?