How do you find the first and second derivative of $(ln(x))^2$ ?

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Answer 1 · 2016-05-23T04:09:56

The first derivative is

$d((lnx)^2)/dx=2*lnx*d(lnx)/dx=2*lnx*1/x$

The second derivative is

$d(2*lnx/x)/dx=2*[lnx'*x-lnx*x']/[x^2]=2*(1-lnx)/(x^2)$

How do you find the first and second derivative of (ln(x))^2(ln(x))^2?