How do you find the first and second derivative of $xlnx^2$ ?

Question

8378 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-07T16:57:59

See below.

First use properties of logarithms to rewrite

$f(x) = xlnx^2 = 2xlnx$

$f'(x) = 2lnx+2$

$f''(x) = 2/x$

How do you find the first and second derivative of xlnx^2xlnx^2?