How do you find the first five terms of each sequence a_1=-3a1=3, a_(n+1)=a_n+nan+1=an+n?

1 Answer
Feb 1, 2017

First five terms are {-3,-2,0,3,7}{3,2,0,3,7}

Explanation:

Às a_1=-3a1=3 and a_(n+1)=a_n+nan+1=an+n

therefore a_2=a_1+1=-3+1=-2a2=a1+1=3+1=2

a_3=a_2+2=-2+2=0a3=a2+2=2+2=0

a_4=a_3+3=0+3=3a4=a3+3=0+3=3

a_5=a_4+4=3+4=7a5=a4+4=3+4=7

Hence, first five terms are {-3,-2,0,3,7}{3,2,0,3,7}