How do you find the horizontal asymptote for $F(x)=(x^2+x-12) / (x^2-4)$ ?

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Answer 1 · 2016-02-28T12:38:14

see explanantion

Tony B

As $x$ becomes very large the remaining elements have less and less influence.

We end up with $" " x^2/x^2 = 1$

$lim_(x->oo) (x^2+x-12)/(x^2-4) = x^2/x^2=+1$

$lim_(x->-oo) (x^2+x-12)/(x^2-4) = x^2/x^2=+1$

How do you find the horizontal asymptote for F(x)=(x^2+x-12) / (x^2-4)F(x)=(x^2+x-12) / (x^2-4)?