How do you find the horizontal asymptote for y = (x + 1)/(x - 1)y=x+1x1?

1 Answer
Apr 1, 2018

Horizontal asymptote is y=1y=1

Explanation:

A vertical asymptote means when as y->+-ooy±, xx tends to some finite number. This is simpler as we know that such a limit is brought out by the denominator, here x-1x1. As x-1->0x10 i.e. x->1x1, it is apparent that y->=-ooy=. Hence x=1x=1 is a vertical asymptote here.

On the contrary, a horizontal asymptote means when x->+-oox±, yy tends to some finite number. Now as when x->=-oox=, 1/x->01x0, we divide numerator and denominator by xx.

and y=lim_(x->oo)(x+1)/(x-1)=lim_(x->oo)(1+1/x)/(1-1/x)

= 1

Hence horizontal asymptote is y=1.
graph{(x+1)/(x-1) [-10, 10, -5, 5]}

Note: Observe that horizontal asymptote = is there only when degree of x in numerator and denominator is same.