Question

How do you find the indefinite integral of `int (1+secpix)^2secpixtanpixdx`?

Answer 1

`int(1+secpix)^2secpixtanpixdx=(1+secpix)^3/(3pi)`

Explanation:

Let `u=1+secpix` then `du=pisec(pix)tan(pix)dx`

and hence `int(1+secpix)^2secpixtanpixdx`

= `intu^2/pidu`

= `u^3/(3pi)`

= `(1+secpix)^3/(3pi)`