How do you find the inflection points for the function $f (x) = 8 x + 3 - 2 sin (x)$ $f(x)=8x+3-2 sin(x)$ ?

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Answer 1 · 2018-05-26T12:03:21

Solve the equation $sin (x) = 0$ $sin(x)=0$ and it must be $cos (x) \neq 0$ $cos(x)ne 0$

$f (x) = 8 x + 3 - 2 sin (x)$ $f(x)=8x+3-2sin(x)$
$f'(x)=8-2cos(x)$
$f''(x)=2sin(x)$
$f'''(x)=2cos(x)$

How do you find the inflection points for the function f(x)=8x+3-2 sin(x)f(x)=8x+3−2sin(x)f(x)=8x+3-2 sin(x)?