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How do you find the inner product $<3,-2,4>*<1,-4,0>$ ?

1 Answer

May 13, 2017

The inner product is $=11$

Explanation:

The inner or dot product of 2 vectors

$vecA= < x_1 , y_1,z_1>$

And

$vecB= < x_2, y_2, z_2>$

is

$vecA.vecB=< x_1 , y_1,z_1>.< x_2, y_2, z_2>$

$=x_1x_2 + y_1y_2 +z_1z_2$

Here, we have

$<3, -2, 4>.<1,-4,0> = (3*1+2*4+4*0)=3+8=11$

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