How do you find the instantaneous velocity at $t = 0$ $t=0$ for the position function $s (t) = 6 t^{2} + 8 t$ $s(t) = 6t^2 +8t$ ?

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Answer 1 · 2018-04-29T01:52:31

$8$ $8$

The position is given by the function $s (t) = 6 t^{2} + 8 t$ $s(t)=6t^2+8t$ .

The velocity is the rate of change of displacement over time, so it'll be the derivative of the position function, i.e. $v(t)=s'(t)=12t+8$ .

So, at $t=0$ , the instantaneous velocity will be:

$s'(0)=12*0+8$

$=0+8$

$=8$

How do you find the instantaneous velocity at t=0t=0t=0 for the position function s(t) = 6t^2 +8ts(t)=6t2+8ts(t) = 6t^2 +8t?