How do you find the integral $int(5x+4)^4dx$ using substitution?

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Answer 1 · 2017-10-05T15:52:44

$=1/25(5x+4)^5+C$

By substitution

$int(5x+4)^4dx$

$u=5x+1=>du=5dx=>dx=(du)/5$

$int(5x+4)^4dx=intu^4*(du)/5=dx$

$=1/5intu^4du=1/5xx1/5u^5+C$

$=1/25u^5+C=1/25(5x+4)^5+C$

How do you find the integral int(5x+4)^4dxint(5x+4)^4dx using substitution?