How do you find the integral of #(cos^4 x sin x) dx# from #[0, pi/3]#?

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Answer 1 · 2015-04-17T03:50:31

Have a look:
#intcos^4(x)sin(x)dx=#
but: #d[cos(x)]=-sin(x)dx#
#=-intcos^4(x)d[cos(x)]=#
#=-cos^5(x)/5|_0^(pi/3)##=31/160#