Question

How do you find the integral of `int sec^2(5x)dx`?

Answer 1

`1/5 tan 5x +C`

Explanation:

Let 5x = u , so that `dx= 1/5 du`

`int sec^2 5x dx = 1/5intsec^2 u du`

=`1/5 tanu +C`

= `1/5 tan 5x +C`