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How do you find the integral of $(x^{2}) (e^{x - 1})$ $(x^2)(e^(x-1))$ ?

1 Answer

Jun 30, 2015

I found $e^{x - 1} [x^{2} - 2 x + 2] + c$ $e^(x-1)[x^2-2x+2]+c$

Explanation:

I used Integration by Parts (twice):
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