Question

How do you find the integration of : ((1-1/x) cos(x-Inx))dx?

Answer 1

`sin(x-ln x)+C`

Explanation:

Substitute `x-ln x= u`. Then we have `(1-1/x)dx=du` and so

`int (1-1/x)cos(x-ln x)dx = int cos u du`
`= sin u+C = sin(x-ln x) + C`