How do you find the intercepts for #2x-y= -4#?

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Answer 1 · 2018-03-24T18:55:29

The intercepts are #(-2,0)# and #(0,4)#

To find the x intercept put #y=0# and solve for x
To find the y intercept put #x=0# and solve for y

At #y=0# , #x=-2#
At #x=0# , #y=4#

So the intercepts are #(-2,0)# and #(0,4)#

Answer 2 · 2018-03-24T18:55:40

The #x#-intercept is #(-2,0)# and the #y#-intercept is #(0,4)#.

The #x#-intercept is the value of #x# when #y# is #0#. Similarly, the #y#-intercept is the value of #y# when #x# is #0#.

So

#x#-intercept #=> 2x -y =-4#

#=> 2x - 0 = -4#

#=> x = -2#

and

#y#-intercept: #=> 2x-y =-4#

#=> 2(0) - y = -4#

#=> y = 4#