How do you find the intercepts for $2 x + y = 6$ $2x+y=6$ ?

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Answer 1 · 2016-11-06T00:31:55

The $x$ $x$ intercept is $(3, 0)$ $(3,0)$ and the $y$ $y$ intercept is $(0, 6)$ $(0, 6)$ .

$2 x + y = 6$ $2color(blue)x+color(red)y=6$

The $x$ $x$ intercept is the point where the line crosses the $x$ $x$ axis.
$y = 0$ $y=0$ everywhere on the $x$ $x$ axis.

To find the $x$ $x$ intercept, substitute $y = 0$ $color(red)y=color(red)0$ into the equation and solve for $x$ $color(blue)x$ .

$2 x + 0 = 6$ $2color(blue)x+color(red)0=6$

$2 x = 6$ $2color(blue)x=6$

$\frac{2 x}{2} = \frac{6}{2} a a a$ $(2color(blue)x)/2 =6/2color(white)(aaa)$ Divide both sides by 2

$x = 3$ $color(blue)x=3$

The $x$ $x$ intercept is then $(3, 0)$ $(3,0)$ .

The $y$ $y$ intercept is the point where the line crosses the $y$ $y$ axis.
$x = 0$ $x=0$ everywhere on the $y$ $y$ axis.

To find the $y$ $y$ intercept, substitute $x = 0$ $color(blue)x =color(blue)0$ into the equation and solve for $y$ $color(red)y$ .

$2 (0) + y = 6$ $2(color(blue)0)+color(red)y=6$

$y = 6$ $color(red)y=6$ .

The $y$ $y$ intercept is then $(0, 6)$ $(0,6)$ .

How do you find the intercepts for 2x+y=62x+y=6?