How do you find the intercepts for $- 2 y + 16 x = - 4$ $-2y + 16x = -4$ ?

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Answer 1 · 2015-11-07T23:55:07

y-intercept = 2
x-intercept = -1/4

Plug zero into x and y, respectively.

let $x = 0$ $x = 0$

$- 2 y + 16 (0) = - 4$ $−2y+16(0)=−4$

$- 2 y = - 4$ $−2y=−4$

$y = 2$ $y=2$ This is the y-intercept

Now let $y = 0$ $y = 0$

$- 2 (0) + 16 x = - 4$ $−2(0)+16x=−4$

$16 x = - 4$ $16x=−4$

$x = - \frac{1}{4}$ $x=-1/4$ This is the x-intercept

How do you find the intercepts for −2y+16x=−4-2y + 16x = -4?