Question

How do you find the intercepts for `3x-2y=-12`?

Answer 1

You set both `xandy` to zero in turn, and see where the other one ends up.

Explanation:

`x`-intercept means `y=0`
`3x-2*0=-12->3x=-12->x=-4->(-4,0)`

`y`-intercept means `x=0`
`3*0-2y=-12->-2y=-12->y=6->(0,6)`
graph{1.5*x+6 [-12.42, 7.58, -1.44, 8.56]}