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How do you find the intercepts for $3 y = - 6 x + 3$ $3y=-6x+3$ ?

1 Answer

Jun 11, 2015

x-intercept $= \frac{1}{2}$ $= 1/2$ ; y-intercept $= 1$ $=1$

Explanation:

The x-intercept is the value of $x$ $x$ when $y = 0$ $y=0$
$XXXX$ $color(white)("XXXX")$ $3 (0) = - 6 x + 3 \Rightarrow x = \frac{1}{2}$ $3(0) = -6x+3 rArr x = 1/2$

The y-intercept is the value of $y$ $y$ when $x = 0$ $x=0$
$XXXX$ $color(white)("XXXX")$ $3 y = - 6 (0) + 3 \Rightarrow y = 1$ $3y = -6(0) +3 rArr y = 1$

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