How do you find the intercepts for $4 x - 3 y = 24$ $4x-3y=24$ ?

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Answer 1 · 2015-06-11T12:21:30

The intercepts are when $x = 0 or y = 0$ $x=0ory=0$

$y$ $y$ -intercept ( $x = 0$ $x=0$ ):
$4 \cdot 0 - 3 y = 24 \to y = \frac{24}{- 3} = - 8 \to (0, - 8)$ $4*0-3y=24->y=24/(-3)=-8->(0,-8)$

$x$ $x$ -intercept ( $y = 0$ $y=0$ ):
$4 x - 3 \cdot 0 = 24 \to x = \frac{24}{4} = 6 \to (6, 0)$ $4x-3*0=24->x=24/4=6->(6,0)$

How do you find the intercepts for 4x−3y=244x-3y=24?