How do you find the intercepts for $f (x) = 2 x^{2} - 5 x - 3$ $f(x) = 2x^2 - 5x -3$ ?

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How do you find the intercepts for $f (x) = 2 x^{2} - 5 x - 3$ $f(x) = 2x^2 - 5x -3$ ?

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Answer 1 · 2015-06-19T13:39:23

Given your function $y = f (x)$ $y=f(x)$
y-inercept: $x = 0, y = - 3$ $x=0, y=-3$
x-intercept: $x_{1} = 3, y = 0$ $x_1=3, y=0$
and $x_{2} = - \frac{1}{2}, y = 0$ $x_2=-1/2, y=0$

Explanation:

First you set $x = 0$ $x=0$ into your equation and get $y = f (0) = - 3$ $y=f(0)=-3$ .
Second you set $y = 0$ $y=0$ and solve the quadratic equation:
$2 x^{2} - 5 x - 3 = 0$ $2x^2-5x-3=0$ using the Quadratic Formula:
$x_{1, 2} = \frac{5 \pm \sqrt{25 + 24}}{4} = \frac{5 \pm 7}{4} =$ $x_(1,2)=(5+-sqrt(25+24))/4=(5+-7)/4=$
$x_{1} = \frac{12}{4} = 3$ $x_1=12/4=3$
$x_{2} = - \frac{2}{4} = - \frac{1}{2}$ $x_2=-2/4=-1/2$

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How do you find the intercepts for $f (x) = 2 x^{2} - 5 x - 3$ $f(x) = 2x^2 - 5x -3$ ?

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Explanation:

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How do you find the intercepts for $f (x) = 2 x^{2} - 5 x - 3$ $f(x) = 2x^2 - 5x -3$ ?