How do you find the intercepts for $f(x) = 4/5x + 7$ ?

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Answer 1 · 2015-06-11T10:29:47

That's when set you $x=0 orf(x)=y=0$

$y$ -intercept:
$x=0->f(x)=7->(0,7)$

$x$ -intercept:
$f(x)=0->4/5x+7=0->4/5x=-7->$

$x=-7/(4/5)=-35/4=-8 3/4->(-8 3/4,0)$
graph{0.8x+7 [-14.545, 5.455, -1.96, 8.04]}

How do you find the intercepts for f(x) = 4/5x + 7 f(x) = 4/5x + 7?