How do you find the intercepts for #x-3y+7=0?

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Answer 1 · 2015-06-19T18:37:37

To find the intercept with the $x$ axis, let $y=0$ and solve to find $x = -7$

To find the intercept with the $y$ axis, let $x=0$ and solve to find $y = 7/3$

This line will intercept the $x$ axis where $y=0$ , so substitute $y=0$ into the equation to get:

$x+7 = 0$

Subtract $7$ from both sides to get $x = -7$ .

So the intercept is at $(-7, 0)$

The line will intercept the $y$ axis where $x=0$ , so substitute $x=0$ into the equation to get:

$-3y+7 = 0$

Add $3y$ to both sides to get:

$7=3y$

Divide both sides by $3$ to get:

$y = 7/3$

So the intercept is at $(0, 7/3)$