How do you find the intercepts for $y = 3 x - 3$ $y=3x-3$ ?

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Answer 1 · 2015-07-02T22:39:22

To find the x-intercept, set $y$ $y$ to zero and solve for $x$ $x$ .
To find the y-intercept, set $x$ $x$ to zero and solve for $y$ $y$ .

$y = 3 x - 3$ $y=3x-3$

X-Intercept

$0 = 3 x - 3$ $0=3x-3$

Add $3$ $3$ to both sides.

$3 = 3 x$ $3=3x$

Divide both sides by $3$ $3$ .

$1 = x$ $1=x$

Switch sides.

$x = 1$ $x=1$

Y-Intercept

$y = 3 (0) - 3$ $y=3(0)-3$

$y = - 3$ $y=-3$

graph{y=3x-3 [-12.87, 12.44, -7.24, 5.42]}

How do you find the intercepts for y=3x−3y=3x-3?