How do you find the intercepts for $y = - 3 x + 3$ $y=-3x+3$ ?

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Answer 1 · 2015-06-14T22:40:02

The intercept with the $y$ $y$ axis is where $x = 0$ $x=0$ , hence $y = - 3 \cdot 0 + 3 = 3$ $y = -3*0 + 3 = 3$ . That is $(0, 3)$ $(0, 3)$

The intercept with the $x$ $x$ axis is where $y = 0$ $y=0$ , hence $0 = - 3 x + 3$ $0 = -3x + 3$ , hence $x = 1$ $x = 1$ . That is $(1, 0)$ $(1, 0)$

To find where $y = - 3 x + 3$ $y = -3x + 3$ intercepts the $y$ $y$ axis, substitute $x = 0$ $x=0$ into the equation to find:

$y = (- 3 \cdot 0) + 3 = 0 + 3 = 3$ $y = (-3*0) + 3 = 0 + 3 = 3$ .

That is $(0, 3)$ $(0, 3)$

To find where $y = - 3 x + 3$ $y = -3x + 3$ intercepts the $x$ $x$ axis, substitute $y = 0$ $y=0$ into the equation to find:

$0 = - 3 x + 3$ $0 = -3x+3$

Add #3x to both sides to get:

$3 x = 3$ $3x=3$

Divide both sides by $3$ $3$ to get:

$x = 1$ $x = 1$ .

That is $(1, 0)$ $(1, 0)$

graph{-3x+3 [-9.5, 10.5, -3, 7]}

How do you find the intercepts for y=−3x+3y=-3x+3?