How do you find the intercepts for $y= -5/(3x)+ 2$ ?

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Answer 1 · 2018-06-01T21:25:38

$x=6/5$

$y=2$

$y= -5/(3x)+ 2$

$y= -5/3x+ 2$

to find y intercept set x=0 and solve for y:

$y= -5/3*0+ 2$

$y=2$

to find x intercept set y = 0 and solve for x:

$0= -5/3x+ 2$

$-2= -5/3x$

$-2*-3/5= -5/3x * -3/5$

$6/5=x$

$x=6/5$

How do you find the intercepts for y= -5/(3x)+ 2y= -5/(3x)+ 2?