How do you find the intercepts of $3 x - 6 y = 24$ $3x-6y=24$ ?

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Answer 1 · 2016-11-30T09:19:44

x=intercept is $(8, 0)$ $(8,0)$ and y-intercept is $(0, - 24)$ $(0,-24)$

All along the $x$ $x$ axis, $y = 0$ $y=0$ and all along the $y$ $y$ axis, $x = 0$ $x=0$

TO find the $x$ $x$ -intercept, make $y = 0$ $y=0$

$3 x - 6 (0) = 24$ $3x-6(0) = 24$
$3 x = 24$ $3x = 24$
$x = 8 \to$ $x = 8" "rarr$ x=intercept is $(8, 0)$ $(8,0)$

TO find the $y$ $y$ intercept, make $x$ $x$ =0

$3 (0) - y = 24$ $3(0) -y = 24$
$- y = 24$ $-y = 24$
$y = - 24 \to$ $y = -24" "rarr$ y-intercept is $(0, - 24)$ $(0,-24)$

How do you find the intercepts of 3x−6y=243x-6y=24?