How do you find the intercepts of $4y = 2x +6$ ?

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Answer 1 · 2016-08-10T21:13:20

$x= -3 and y = 3/2$

A line has an x-intercept and a y-intercept, the points where it crosses the x-axis and the y-axis respectively.

On the y-axis, $x = 0$ and on the x-axis, $y = 0.$

In $4y = 2x +6$

To find the y-intercept , make $x=0$

$4y = 0 +6" "rArr y = 6/4 = 3/2$

To find the x-intercept , make $y=0$

$0 = 2x +6" " rArr 2x =-6 " " rArr x = -3$

How do you find the intercepts of 4y = 2x +6 4y = 2x +6?