How do you find the intercepts of the line $x-y=11$ ?

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Answer 1 · 2016-09-05T16:12:57

Intercept on $x$ -axis is $- 11$ and intercept on $y$ -axis is $-11$ .

Intercept on $x$ -axis is formed where $y=0$ , hence putting $y=0$ in $x-y=11$ , we get $x=11$ . Hence, intercept on $x$ -axis is $11$ .

Intercept on $y$ -axis is formed where $x=0$ , hence putting $x=0$ in $x-y=11$ , we get $-y=11$ or $y=-11$ . Hence, intercept on $y$ -axis is $-11$ .

How do you find the intercepts of the line x-y=11x-y=11?