How do you find the intercepts of the line #x-y=11#? Algebra Graphs of Linear Equations and Functions Intercepts by Substitution 1 Answer Shwetank Mauria Sep 5, 2016 Intercept on #x#-axis is #- 11# and intercept on #y#-axis is #-11#. Explanation: Intercept on #x#-axis is formed where #y=0#, hence putting #y=0# in #x-y=11#, we get #x=11#. Hence, intercept on #x#-axis is #11#. Intercept on #y#-axis is formed where #x=0#, hence putting #x=0# in #x-y=11#, we get #-y=11# or #y=-11#. Hence, intercept on #y#-axis is #-11#. Answer link Related questions What is the x and y Intercepts? How many intercepts can a line have? How do you use substitution to find intercepts? How do you identify the intercepts on a linear graph? How do you use the x and y intercepts to graph a linear equation? How do you find the x and y intercept for #y=2x+3#? How do you find the x intercept for #y=2#? What is the y intercept for the #y=2# graph? What is the y intercept for #x=-1#? How do you find the intercepts of #x^2y-x^2+4y=0#? See all questions in Intercepts by Substitution Impact of this question 1923 views around the world You can reuse this answer Creative Commons License