How do you find the intercepts of $y = - 3 - 3 x$ $y=-3-3x$ ?

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Answer 1 · 2016-06-25T15:35:41

$x = - 1 and y = - 3$ $x= -1 and y = -3$

The intercepts are the points on the axes.

All points on the x-axis have a y-value = 0.
All points on the y-axis have an x-value = 0.

To find the y-intercept, make x = 0 and solve for y.

$y = - 3 - 3 x$ $y=-3-3x$ becomes $y = - 3 - 3 (0)$ $y = -3 -3(0)$

$y = - 3$ $y = -3$

To find the x-intercept, make y = 0 and solve for x.

$y = - 3 - 3 x$ $y=-3-3x$ becomes $0 = - 3 - 3 x$ $0 = -3-3x$
$3 x = - 3$ $3x = -3$

$x = - 1$ $x = -1$

How do you find the intercepts of y=−3−3xy=-3-3x?