How do you find the intercepts of #y=-3-3x#?

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Answer 1 · 2016-06-25T15:35:41

#x= -1 and y = -3#

The intercepts are the points on the axes.

All points on the x-axis have a y-value = 0.
All points on the y-axis have an x-value = 0.

To find the y-intercept, make x = 0 and solve for y.

#y=-3-3x# becomes #y = -3 -3(0)#

#y = -3#

To find the x-intercept, make y = 0 and solve for x.

#y=-3-3x# becomes # 0 = -3-3x#
#3x = -3#

# x = -1#