How do you find the inverse of #f(x)=(2-3x)/4#?

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Answer 1 · 2015-09-01T16:33:45

#f^-1(x) = (2 - 4x)/3#

#f(x) = (2 - 3x)/4 => f(x) = y:#

#y = (2 - 3x)/4 =># switch # x & y:#

#x = (2 - 3y)/4 =># solve for # y:#

#x/1 = (2 - 3y)/4 =># now cross multiply:

#2 - 3y = 4x =># subtract 2 from both sides:

#-3y = 4x - 2 =># divide both sides by -3:

#y = (2 - 4x)/3 =># this is the inverse function, so:

#f^-1(x) = (2 - 4x)/3#