How do you find the inverse of $y = 6x – 3$ ?

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Answer 1 · 2015-09-13T14:04:34

Interchange x and y and turn the equation in terms of y.

y=6x-3

x=6y-3

x+(-3)=6y+3+(-3)

$(x-3)/6$ = $(6y)/6$

y= $(x-3)/6$

Answer 2 · 2015-09-13T14:05:43

By solving with respect to x.Hence

$y=6x-3=>y+3=6x=>x=1/6(y+3)$

so $y^-1=1/6(x+3)$

How do you find the inverse of y = 6x – 3 y = 6x – 3?