How do you find the limit #lim (4^(1+x)-4^(1-x))/(2^(1+x)-2^(1-x))# as #x->0#? Calculus Limits Infinite Limits and Vertical Asymptotes 1 Answer Konstantinos Michailidis Dec 31, 2016 We have that #lim (4^(1+x)-4^(1-x))/(2^(1+x)-2^(1-x))= lim_(x->0) ((2^(1+x)+2^(1-x))*(2^(1+x)-2^(1-x)))/(2^(1+x)-2^(1-x))= lim_(x->0) ((2^(1+x)+2^(1-x))*(cancel(2^(1+x)-2^(1-x))))/(cancel(2^(1+x)-2^(1-x)))= lim_(x->0) (2^(1+x)+2^(1-x))=4# We use the identity #a^2-b^2=(a+b)*(a-b)# where #a=2^(1+x)# and #b=2^(1-x)# Answer link Related questions How do you show that a function has a vertical asymptote? What kind of functions have vertical asymptotes? How do you find a vertical asymptote for y = sec(x)? How do you find a vertical asymptote for y = cot(x)? How do you find a vertical asymptote for y = csc(x)? How do you find a vertical asymptote for f(x) = tan(x)? How do you find a vertical asymptote for a rational function? How do you find a vertical asymptote for f(x) = ln(x)? What is a Vertical Asymptote? How do you find the vertical asymptote of a logarithmic function? See all questions in Infinite Limits and Vertical Asymptotes Impact of this question 1298 views around the world You can reuse this answer Creative Commons License