Question

How do you find the limit `lim (pi^x-pi)/(pi^(2x)-pi^2)` as `x->1`?

Answer 1

`1/(2pi)`

Explanation:

`lim_(x->1) (pi^x-pi)/(pi^(2x)-pi^2)=lim_(x->1) (pi^x-pi)/((pi^(x)-pi)(pi^(x)+pi))=1/(2pi)`